Hi, so I currently run up front a W&W cycles 3x16" 40 spoke drop centre rim on a modern timken bearing star hub with a W&W cycles springer OEM replica drum brake. This is all fitted to a W&W repop classic 1939-57 type springer fork. This is being run on a 1995 stock softail frame with the OEM softail 3x16" rim on the back.
I am currently replacing the rim on the front wheel due to a pothole taking a big chunk out of the rim and am in the process of re-lacing the hub to the new replacement rim (same type, 40 spoke drop centre).
Ive read up on the process and took plenty pics etc to ensure I can put it all together which is going fine, I have trued my wheels in the past and got them nice and straight but haven't fully replaced a rim before.
My question is to do with the offset. I noticed before I unlaced the front rim that with the rim on the front axle (tyre removed) and with all spacers, brake drum together etc. the rim outer edge measures approx. 5cm away from the brake side fork leg and approx. 4 cm from the other fork leg. I also measured the rim offset on its side, lying on a flat surface laying a straight edge across the brake side wheel hub face to the outside edge of the rim and got approx. 1.5cm.
I have heard that it is normal for there to be a slight offset on these 16" wheels to allow clearance for tyres but I dont have a manual that would confirm this for these old style starhub / springer set ups. Can anyone confirm if this sounds correct?
My normal approach would be to centre the rim so it is completely in the middle of the fork legs and im not using any additional spacers or anything "custom". Its all the OEM axle and spacers designed to work with the OEM brake, wheel and springer.
For what its worth, the bike was riding straight and good with no abnormalities in the steering!
Thanks in advance
I am currently replacing the rim on the front wheel due to a pothole taking a big chunk out of the rim and am in the process of re-lacing the hub to the new replacement rim (same type, 40 spoke drop centre).
Ive read up on the process and took plenty pics etc to ensure I can put it all together which is going fine, I have trued my wheels in the past and got them nice and straight but haven't fully replaced a rim before.
My question is to do with the offset. I noticed before I unlaced the front rim that with the rim on the front axle (tyre removed) and with all spacers, brake drum together etc. the rim outer edge measures approx. 5cm away from the brake side fork leg and approx. 4 cm from the other fork leg. I also measured the rim offset on its side, lying on a flat surface laying a straight edge across the brake side wheel hub face to the outside edge of the rim and got approx. 1.5cm.
I have heard that it is normal for there to be a slight offset on these 16" wheels to allow clearance for tyres but I dont have a manual that would confirm this for these old style starhub / springer set ups. Can anyone confirm if this sounds correct?
My normal approach would be to centre the rim so it is completely in the middle of the fork legs and im not using any additional spacers or anything "custom". Its all the OEM axle and spacers designed to work with the OEM brake, wheel and springer.
For what its worth, the bike was riding straight and good with no abnormalities in the steering!
Thanks in advance
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